(4/5x-10)^2=8x

Solution for (4/5x-10)^2=8x equation:

(4/5x-10)^2=8x

We move all terms to the left:

(4/5x-10)^2-(8x)=0


Domain of the equation: 5x-10)^2!=0

x∈R


We add all the numbers together, and all the variables

-8x+(4/5x-10)^2=0

We multiply all the terms by the denominator


-8x*5x-10)^2+(4=0

We add all the numbers together, and all the variables

-8x*5x=0

Wy multiply elements

-40x^2=0

a = -40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-40)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-80}=0$